Flexiple spent good amount of time understanding our requirements, resulting in accurate recommendations and quick ramp up by quality developers.
Overall Flexiple brought in high-level of transparency with quick turnarounds in the hiring process at a significantly lower cost than any alternate options.
Flexiple has been instrumental in helping us grow at a fast pace. Their vetting process for engineers is top notch and they connected us with quality talent quickly.
Flexiple Developers are reviewed on their experience and complexity of products built. Those who display depth and have worked on end-to-end projects are given an introductory call.
Over a call, the developer’s ability to communicate in an articulate manner is tested. A deeper understanding of the candidate’s technical experience and also motivation to freelance is achieved.
Over one or more F2F interviews, the developer’s involvement and performance in building complex software products are assessed. This sets the platform to delve deeper into technology-specific discussions.
Developers' mental agility and problem-solving abilities are tested through a coding test involving algorithmic as well as skill-specific problems. A mixture of live evaluation and timed coding tests is used.
The live experience of working with developers is verified by reaching out to past clients and/or employers. Inputs on various qualitative factors such as reliability, punctuality, communication and responsiveness are received.
Performance during each engagement is continually assessed. Our developers are expected to maintain Flexiple standards across all engagements with our customers.
Java is an object-oriented programming language developed by James Gosling and his colleagues at Sun Microsystems in the early 1990s. There has been a significant increase in the number of Java developers over the years. It went from 1.5 Million in 2003 to 7 Million in 2007 when Java became an open-source. The year 2020 marks the 25th anniversary of Java, and it has still managed to maintain its position in the top 3 most popular programming languages. A lot of enterprise companies use Java for their server-side programming because it is exceptionally robust and user-friendly.
If you’re looking for a freelance Java developer, this guide will come handy. We’ve included everything you need to know about the hiring process.
But before we get into the fundamentals of hiring a freelance Java developer, let’s delve into some interesting facts about Java.
We have broken the sections into the following parts:
1. Let's introduce Java to you.
2. Why is Java widespread?
3. Writing the Job Description
4. Interview Questions for hiring a Java developer
- Basic Questions
- Advanced Questions
- Data Structures/Algo Questions
Below are some key points that we at Flexiple have learned through trial and error - a process of filtering through over 15,000 developers.
Now that you have made a quality JD, it can still be tricky to evaluate the skills of your applicants. To help you with that, we have created a pool of questions that a good Java developer should be comfortable with.
It is important to note that the ability to answer these questions doesn't imply that you have a top quality candidate. But it definitely is a big step in that direction.
To help you navigate through these questions, we’ve categorized the interview questions in 3 parts:
A. Basic concepts: Includes all basic concepts used across languages but we've focused on its significance in Java. This section will give you an understanding of how strong their programming foundation is.
B. Advanced concepts: Includes all concepts that someone with higher expertise should know.
C. DS/Algorithm questions: To test the logical capability of the candidate.
class ValidParenthesesFunc {
func isValid(_ s: String) -> Bool {
var stc = [Character]()
for char in s {
if char == "(" || char == "[" || char == "{" {
stc.append(char)
} else if char == ")" {
guard stc.count != 0 && stc.removeLast() == "(" else {
return false
}
} else if char == "]" {
guard stc.count != 0 && stc.removeLast() == "[" else {
return false
}
} else if char == "}" {
guard stc.count != 0 && stc.removeLast() == "{" else {
return false
}
}
}
return stc.isEmpty
}
}
The above code will input 0(false).
import java.util.Scanner;
public class Palindrome {
public static void main (String[] args) {
String original, reverse = "";
Scanner in = new Scanner(System.in);
int length;
System.out.println("Enter a number or a string");
original = in.nextLine();
length = original.length();
for (int i =length -1; i>;=0; i--) {
reverse = reverse + original.charAt(i);
}
System.out.println("The reverse is: " +reverse);
if(original.equals(reverse))
System.out.println("The string is a palindrome");
else
System.out.println("The stringis not a palindrome");
}
}
Output: For String- Enter a number or a string sam The reverse is: mas The string is not a palindrome For Number-Enter a number or a string 99 The reverse is: 99 The number is a palindrome
class Test {
public static void main(String args[])
{
String str1 = new String("Hello World");
String str2 = new String("Hello World");
String str3 = "Hello World";
String str4 = "Hello World";
int a = 0, b = 0, c = 0;
if (str3 == str4)
a = 1;
else
a = 2;
if (str1.equals(str3))
b = 1;
else
b = 2;
if (str1 == str4)
c = 1;
else
c = 2;
System.out.println("a= " + a + " b= " + b + " c= " + c);
}
}
D. a=1 b=1 c=2 because a new memory is created when we make an object with the help of the ‘new’ keyword, and the reference variable contains the memory location. Here the memory is created with the same string twice, but since we are comparing objects and not strings, the object will point to a different memory location and so they are not equal.
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